Function printNPattern – CTS PATTERN

Print a descending staircase pattern of a given number N

Understand the Problem

Problem Statement

Implement the function printNPattern(int N) that accepts an integer N as input and prints a descending staircase pattern using the number N.

The pattern should have N rows, where the first row contains N copies of the number N separated by spaces, the second row contains (N-1) copies, and so on, until the last row contains just one copy of N.

Constraints

1 ≤ N ≤ 100 (the number of rows and starting value)
N is a positive integer
Each row should contain the appropriate number of N's separated by spaces
Each row should end with a newline character

Examples

Example 1

Input

Output

Explanation

For N=5, the first row has 5 copies of 5, the second row has 4 copies, and so on until the last row has just 1 copy.

Example 2

Input

Output

Explanation

For N=4, the pattern has 4 rows with decreasing numbers of 4's: 4, 3, 2, and 1 copies respectively.

Solution

void printNPattern(int N){
    for(int i=0;i<=N-1;i++){
        for(int j=0;j<N-i-1;j++){
            printf("%d ",N);
        }
        printf("%d\n",N);
    }
}

Time:O(N²)

Space:O(1)

Approach:

The C solution uses a nested loop structure:

Outer loop (i): Runs from 0 to N-1, representing each row
Inner loop (j): Runs from 0 to N-i-2, printing spaces between numbers
First printf: Prints N followed by a space for all but the last number in each row
Second printf: Prints the final N in each row without a trailing space, followed by a newline

This ensures proper formatting without extra spaces at the end of lines.

Visual Explanation

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